Question 154321
Use the following properties of exponents:
{{{1/a^(-n)=a^n}}}
{{{a^(-n)=1/a^n}}}
So
{{{(x^(-3)y^(-2))/z^(-4)}}}
={{{x^-3*y^-2*(1/z^-4)}}}
={{{(1/x^3)(1/y^2)*z^4}}}
={{{z^4/(x^3y^2)}}}