Question 154364
{{{(25f)/(5f-25)+(4f)/(25f-125)}}} Start with the given expression




{{{(25f)/(5(f-5))+(4f)/(25f-125)}}} Factor the first denominator



{{{(25f)/(5(f-5))+(4f)/(25(f-5))}}} Factor the second denominator



{{{(5/5)((25f)/(5(f-5)))+(4f)/(25(f-5))}}} Multiply the first fraction by {{{5/5}}}



{{{(125f)/(25(f-5))+(4f)/(25(f-5))}}} Combine and multiply the fractions.



{{{(125f+4f)/(25(f-5))}}} Add the fractions. This is now possible since the denominators are equal.



So {{{(25f)/(5f-25)+(4f)/(25f-125)=(125f+4f)/(25(f-5))}}} where {{{f<>5}}}