<PRE><B>Question 154298</B>
The length of a rectangle is 5 less than thrice its width. Find the dimensions if the area is 112 squared cm.
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L = 3W - 5 (The length of a rectangle is 5 less than thrice its width)
L*W = 112
Sub for L
(3W-5)*W = 112
3w^2 - 5W - 112 = 0
*[invoke solve_quadratic_equation 3,-5,-112]
Ignore the negative answer, so W = 7 (the online solver always uses x)
W = 7
L = 3*7 - 5 = 16


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