Question 154247
A right triangle with a hypotenuse of 5 and a base on the x coordinate of 4 the angle at the origin is not given. I'm instructed to find the six trig functions of that angle. I'm like thinking something along the lines of solve for angle measure and then I'm lost. 
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r = 5 ; x = 4
solve for "y"
y = sqrt(r^2 - x^2)
y = sqrt(25 - 16) = 3
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sin(angle) = y/r = 4/5 ; csc(angle) = 5/4
cos(angle) = x/r = 3/5 ; sec(angle) = 5/3
tan(angle) = y/x = 3/4 ; ctn(angle) = 4/3
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The second one is find the values of an angle (theta) (with the line through it) in standard position whose terminal side passes through point p with P at (8,15)
tan(theta) = 15/8
tan^-1(15/8) = 61.93 degrees
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Cheers,
Stan H.