Question 154207
{{{(q - 3)7 + (q - 3)q }}} Start with the given expression.



Let {{{z=q-3}}}. So we now get:



{{{z*7 + z*q }}} Replace {{{q-3}}} with "z"



{{{z(7 + q) }}} Factor out the GCF {{{z}}}



{{{(q-3)(7 + q) }}} Plug in {{{z=q-3}}}



So {{{(q - 3)7 + (q - 3)q }}} factors to {{{(q-3)(7 + q) }}}