Question 154110
Let {{{r}}}= the number of cartons of Regular produced
Let {{{s}}}= the number of cartons of Super produced
Then,
{{{.15r}}}= the amount of DEET used in {{{r}}} cartons of Regular
{{{.25s}}}= the amount of DEET used in {{{s}}} cartons of Super
and
{{{24*(r + s)}}} is the ounces of chemical produced
therefore,
{{{24*(.15r + .25s)}}} is the ounces of DEET produced
59,400 ounces of DEET are available, so
{{{24*(.15r + .25s) <= 59400}}}
{{{.15r + .25s <= 2475}}}
The problem says
{{{r >= 2s}}}
In dollars, the labor costs are
{{{C = 8r + 6s}}}
These can be plotted as {{{r}}} vs {{{s}}}