Question 154132
Using your calculator graph the function f(x) = x 2 + 2x – 3 over the interval
[-5,5]. Approximate any local maxima and local minima. Round your answers to two decimal places
*[invoke solve_quadratic_equation 1,2,-3]
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For the minimum: set the 1st derivative = to zero.
2x+2 = 0
x = -1
f(-1) = 1 - 2 - 3 = -4
So the minimum is as (-1,-4)