Question 154054
The equation "log 6(3m-2) + log 5 = log 9" contains an error.
Note that log(a+b) is not equal to log(a) + log(b).
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To start
{{{6^(3m-2)+5=9}}}
{{{6^(3m-2)=4}}}
{{{(3m-2)log6=log4}}}
....