Question 154162
x squared+5x+6 over x squared+8x/2x squared+5x+2 over 2x squared+x
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[(x^2 + 5x + 6)/(x^2 + 8x)] / [(2x^2 + 5x + 2)/(2x^2 + x)]

Factor where you can: 

[(x+3)(x+2)/(x(x+8))] / [(2x+1)(x+2))/(x(2x+1))]

Invert the denominator and multiply:

[(x+3)(x+2)/(x(x+8))] * [(x(2x+1)/ (2x+1)(x+2))]

Cancel any factor that is common to a numerator and a denominator
such as x, (x+2) , (2x+1) 

= [(x+3)/(x+8)] * [1/1]]

= (x+3)/(x+8)

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Cheers,
Stan H.