Question 154051
Let x be the distance the student jogs, the the distance the student walks is 8-x.
The time jogging is {{{x/9}}}.
The time walking is {{{(8-x)/5}}}
As the time jogging + the time walking = 1 hour, we have
{{{x/9+(8-x)/5=1}}}
Solving for x, we have
{{{45(x/9+(8-x)/5)=1*45}}}   (multiply both sides by 45)\
{{{5x +9(8-x)=45}}}
{{{5x+72-9x=45}}}
{{{-4x=-27}}}
{{{x = 27/4}}}
so the student jogs {{{27/4}}} miles.