Question 153938
reducing this to a quadratic by finding a root is one way to factor


possible roots are factors of 4 (±1,±2,±4) divided by factors of 3 (±1,±3)
__ a root is a value for v that makes the expression equal to zero


2 is a root __ 3(2^3)-6(2^2)+2(2)-4=0


if 2 is a root, then v-2 is a factor


(3v^3-6v^2+2v-4)/(v-2)=(3v^2+2) __ this will not factor further


so, 3v^3-6v^2+2v-4=(v-2)(3v^2+2)