Question 153882
An airplane left an airport flying at at 180 mph.  A jet that flies at 333 mph left 1 hour later.  The jet follows tthe same route as the airplane on parallel altitudes.  How many hours will it take the jet to catch up with the airplane?
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This problem needs you to apply the "distance formula":
d = rt
where
d is distance
r is rate or speed
t is time
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"distance airplane traveled" = "distnce jet traveled"
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Let x = hours "airplane" was flying
x-1 = hours "jet" was flying
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180x = 333(x-1)
180x = 333x - 333
180x + 333 = 333x
333 = 153x
333/153 = x
2.176 hours = x
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