Question 153782
Let the three consecutive odd integers be n-2,n,n+2.
Then their sum is n-2+n+n+2.
As the sum is 279, we have
n-2+n+n+2=279
Solving for n, we have
3n=279
n= 279/3
n= 93
So the three consecutive odd integers are 91,93,95.