Question 153844
I'm assuming that you meant to write {{{5x-2y=0}}} 



{{{5x-2y=0}}} Start with the given equation.



{{{-2y=0-5x}}} Subtract {{{5x}}} from both sides.



{{{-2y=-5x+0}}} Rearrange the terms.



{{{y=(-5x+0)/(-2)}}} Divide both sides by {{{-2}}} to isolate y.



{{{y=((-5)/(-2))x+(0)/(-2)}}} Break up the fraction.



{{{y=(5/2)x+0}}} Reduce.



So the equation {{{y=(5/2)x+0}}} is now in slope intercept form {{{y=mx+b}}} where the slope is {{{m=5/2}}} and the y-intercept is {{{b=0}}} note: the y-intercept is the point *[Tex \LARGE \left(0,0\right)]




Note: {{{y=(5/2)x+0}}} can be written as {{{y=(5/2)x}}}