Question 153718
The sum of the digits of a three-digit number is 15.  The tens place digit is twice the hundreds-place digit, and the ones place digit is 1 less than the hundreds-place digit.  Find the three digit number.
.
Let x = hundreds-place digit
then
2x = tens-place digit
x-1 = ones-place digit
.
x + 2x + (x-1) = 15
4x - 1 = 15
4x = 16
x = 4 (hundreds-place digit)
2x = 8 (tens-place digit)
x-1 = 3 (ones-place digit)
.
Therefore you 3 digit number is:
483