Question 153618
The standard form of a parabola with its axis parallel to x-axis is:
{{{(y-k)^2=4p(x-h)}}}
Its vertex is (h, k)
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SOLUTION:
Re-write the equation in standard form:
{{{(y-1)^2=4*1*(x-0)}}}
So h = 0, k = 1
Thus the vertex is (0, 1).
{{{graph(300,300,-10,10,-10,10,1+2sqrt(x),1-2sqrt(x))}}}