Question 153513
1.{{{x=(1/5)y}}}
2.{{{3x+2y=26}}}
Substitute eq. 1 into eq. 2,
2.{{{3x+2y=26}}}
{{{3(1/5)y+2y=26}}}
{{{(3/5)y+2y=26}}}
{{{(3/5)y+(10/5)y=26}}}
{{{(13/5)y=26}}}
{{{y=26*(5/13)}}}
{{{highlight(y=10)}}}
From 1,
1.{{{x=(1/5)y}}}
{{{x=(1/5)10}}}
{{{highlight(x=2)}}}
Check the answer using eq. 2,

2.{{{3x+2y=26}}}
{{{3(2)+2(10)=26}}}
{{{6+20=26}}}
{{{26=26}}}
True, good answer.