Question 153502
Substitute a=(1/2) for better clarity
{{{(1/2)*ln(x+1)-(1/2)*ln(x-1)+ln(C)=ln((x+1)^a)-ln((x-1)^a)+ln(C)}}}

{{{(1/2)*ln(x+1)-(1/2)*ln(x-1)+ln(C)=ln((x+1)^(a)/(x-1)^(a))+ln(C)}}}
{{{(1/2)*ln(x+1)-(1/2)*ln(x-1)+ln(C)=ln(C(x+1)^(a)/(x-1)^(a))}}}
In final form,
{{{(1/2)*ln(x+1)-(1/2)*ln(x-1)+ln(C)=ln(C((x+1)/(x-1))^(1/2))}}}