Question 153464
To find g(m+1), simply substitute x = m+1 into 2x^2-4x+2, and then simplify the expression.
{{{g(m+1)}}}
={{{2(m+1)^2-4(m+1)+2}}}
={{{2(m^2+2m+1)-4(m+1)+2}}}
={{{2m^2+4m+2-4m-4+2}}}
={{{2m^2+4m-4m+2-4+2}}}
={{{2m^2}}}