Question 153426
x-10/4 + 2/5 = - x/3
Re-writing:
{{{x-(10/4)+(2/5)=(-x/3)}}}
Arranging similar terms:
{{{x+(x/3)=(10/4)-(2/5)}}}
{{{(3x+x)/3=(50-8)/20}}}
{{{4x/3=42/20}}}, cross multiply
{{{4x=126/20}}} ---> {{{cross(4)*x/cross(4)=126/(4*20)}}}
{{{x=(126/80)}}} divide both numerator & denominator by 2:
{{{x=63/40}}}
</pre><font size=4><b>Thank you,
Jojo</pre>