Question 153449
{{{planA=(54.99/month)+freePHONE}}} 
{{{planB=(49.99/month)+129(PHONE)}}}
Let's equate the 2 plans times no. of months "x" for each plan:
{{{planA(x)=PLanB(x)}}}
{{{(54.99/month)(x)=(49.99/month)(x)+129}}}
{{{(54.99/month)(x)-(49.99/month)(x)=129}}}
{{{x((54.99-49.99)/month)=129}}} ------------> {{{x*((5)/month)=129}}}
{{{x*cross(5)/month(cross(5))=cross(129)25.8/cross(5)}}} , cross multiply:
{{{x=25.8months}}}
Let's try usage of {{{25months}}} for each plan:
planA:
{{{(54.99/cross(month))(25cross(months))=1374.75}}}
planB:
{{{(49.99/cross(month))(25cross(months))+129=1378.75}}}
IN 25 MONTHS, PLAN A STILL A BETTER CHOICE
Let's try 26 months:
plan A:
{{{(54.99/cross(month))(26cross(months))=1429.74}}}
plan B:
{{{(49.99/cross(month))(26cross(months))+129=1428.74}}}
THERE YOU GO, YOU START SAVINGS IN CHOOSING PLAN B WHEN YOU REACH 26 MONTHS OF USAGE. TRY 36 MONTHS? 48 MONTHS?
</pre><font size=4><b> Thank you,
Jojo</pre>