Question 153368
Rewrite, using positive exponents:
{{{((-2)^0)*(3x^(-2)(y^(-2)))^(-1)}}}
First, anything to the zero power is equal to 1 {{{x^0 = 1}}}, so {{{(-2)^0 = 1}}}, so now you have:
{{{1*(3x^(-2)*(y^(-2)))^(-1)}}} You can remove the inner parentheses as they are not needed.
{{{(3x^(-2)*y^(-2))^(-1)}}} To raise an exponent to a power, you multiply the exponents. {{{(-1)*(-2) = 2}}}
{{{3x^2*y^2)}}}