Question 153311
can you please help me solve and check using the substitution method.
 {{{system(3x+y=5, -2x+3y=4)}}}
<pre><font size = 4 color = "blue"><b>
Solve the first for {{{y}}}

{{{3x+y=5}}}
{{{y=5-3x}}}

Substitute {{{(5-3x)}}} for {{{y}}} in the second equation

{{{-2x+3*y=4}}}
{{{-2x+3(5-3x)=4}}}
{{{-2x+15-9x=4}}}
{{{-11x=-11}}}
{{{x=1}}}

Now substitute {{{(1)}}} for{{{x}}} in {{{y=5-3x}}}

{{{y=5-3x}}}
{{{y=5-3(1)}}}
{{{y=5-3}}}
{{{y=2}}}

So the solution is (x,y) = (1,2)

Edwin</pre>