Question 153152
Write as the sum/difference of logs:
{{{ln(xy/5z^2)}}} It's not clear from your post whether it's {{{(5z)^2}}} or {{{5*z^2}}}
I.ll assume {{{(5z)^2}}}
{{{ln(xy/(5z)^2) = ln(xy)-ln((5z)^2)}}}={{{ln(x)+ln(y)-2*ln(5z) = ln(x)+ln(y)-2*ln(5)+2*ln(z)}}}