Question 153177
9 - x square over y square divided by 3 - x over y
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[(9-x^2)/y^2] / [(3-x)/y]
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Invert the denominator and multiply:
[(9-x^2)/y^2] * [y/(3-x)]
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Cancel factors common to numerator and denominator to get:
(3+x)/y
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Cheers,
Stan H.