Question 153170
Let x= the first percentage (applied to 100000)
Let y = the second percentage (applied to the difference between the sales and 100000)
If one salesperson earned $8500 on sales of $175000 

then 
{{{100000x+(175000-100000)y=8500}}}

and another sales person earned $14,800 on sales of $280,000 
then

{{{100000x+(280000-100000)y=14800}}}

Then 2 equations are:
{{{100000x+75000y = 8500}}}
{{{100000x+180000y = 14800}}}

doing 1st eq by -1
{{{-100000x-75000y = -8500}}}
{{{100000x+180000y = 14800}}}

adding both equations we have:

105000y=6300
then y=0.06 (6%)
{{{100000x+180000(0.06) = 14800}}}
then
{{{100000x = 14800-10800=4000}}}
then x=0.04 (4%)



Answer: 1st percentage is 4% and the second is 6%