Question 153015
If to be based on 15 sample PC which 9 are infected, it follows:
{{{9/15}}} ---------> {{{cross(9)3/cross(15)5=3/5}}}
For every 5 PC, 3 are infected by proportion.
{{{(3/5)100}}}=60% of the PC are with virus.
So if there are 202 in total:
{{{(202)(60/100)=202*0.60=121.2}}}
Conclusion: Estimated infected about 121 PCs
Thank you,
Jojo