Question 152387
Note that 
{{{x^2+5x+4}}} can be factored into (x+4)(x+1)
{{{x^2-9)}}} can be factored into (x+3)(x-3)

{{{((x^2+5x+4)/(x+1))/((x+3)^2/(x^2-9))}}}
={{{(((x+4)(x+1))/(x+1))/((x+3)^2/((x+3)(x-3)))}}}
={{{(x+4)/((x+3)/(x-3))}}}
={{{(x+4)*(x-3)/(x+3)}}}