Question 153157
Find the vertex and axis of symmetry of the following parabola. 
f(x) = x^2 - 6x + 11 
x^2-6x+9 = y - 11 + 9
(x-3)^2 = y-2
---------------
Axis of symmetry at x = 3
Vertex: (3,2)
===================
Cheers,
Stan H.