Question 153150
4x^2+10x+25=(4x^2+20x+25) - how do I get the answer as (4x^2+20x+25)
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That is not the answer to the problem you have posted.
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Your Problem:
4x^2+10x+25=(4x^2+20x+25)
Subtract 4x^2 from both sides.
Subtract 10x from both sides.
Subtract 25 from both sides. 
You are left with 0 = 10x
x = 0
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Cheers,
Stan H.