Question 152961
12=(x+3)^2-2
12=x^2+6x+9-2
x^2+6x+7-12=0
x^2+6x-5=0
{{{ graph( 300, 200, -10, 5, -15, 10, x^2 +6x -5) }}} (graph 300x200 pixels, x from -10 to 5, y from -15 to 10, x^2 +6x -5).