Question 153107

{{{(x-5)(x^2-3x-2)}}} Start with the given expression.



{{{x(x^2-3x-2)-5(x^2-3x-2)}}} Expand.



{{{(x)*(x^2)+(x)*(-3x)+(x)*(-2)+(-5)*(x^2)+(-5)*(-3x)+(-5)*(-2)}}} Distribute.



{{{x^3-3*x^2-2*x-5*x^2+15*x+10}}} Multiply.



{{{x^3-8*x^2+13*x+10}}} Now combine like terms.



 So {{{(x-5)(x^2-3x-2)}}} expands to {{{x^3-8*x^2+13*x+10}}}.



In other words, {{{(x-5)(x^2-3x-2)=x^3-8*x^2+13*x+10}}}.