Question 153089
Solve for x:
{{{x^2+72 = 12x}}} First, subtract 12x from both sides.
{{{x^2-12x+72 = 0}}} The trinomial is not factorable, so use the quadratic formula: {{{x = (-b+-sqrt(b^-4ac))/2a}}}, where a = 1, b = -12, and c = 72.
{{{x = (-(-12)+-sqrt((-12)^2-4(1)(72)))/2(1)}}}
{{{x = (12+-sqrt(144-288))/2}}}
{{{x = (12+-sqrt(-144))/2}}}
{{{x = (12+-12sqrt(-1))/2}}}
{{{x = 6+6i}}} or {{{x = 6-6i}}}