Question 152836
Let x be the speed of the shuttle.
Let y be the satellite's launching speed relative to the shuttle.
So if launched ahead of the shuttle the satellite's speed is x + y.
if launched to the rear of the shuttle the satellite's speed is x - y.
Thus according to the given information:
x + y = 24,200 ...........(1)
x - y = 21,400 ...........(2)
Adding (1) and (2) together, we have
x + y + x - y = 24,200 + 21,400
2x = 45,600
x = 22,800
Substituting x = 22,800 into equation (1), we have
22,800 + y = 24,200
Solving for y,we obtain
y = 24,200 - 22,800 = 1,400
Therefore the speed of the shuttle is 22,800 km/h, and the satellite's launching speed relative to the shuttle is 1,400 km/h