Question 153008


{{{5x-2y=3}}} Start with the given equation.



{{{-2y=3-5x}}} Subtract {{{5x}}} from both sides.



{{{-2y=-5x+3}}} Rearrange the terms.



{{{y=(-5x+3)/(-2)}}} Divide both sides by {{{-2}}} to isolate y.



{{{y=((-5)/(-2))x+(3)/(-2)}}} Break up the fraction.



{{{y=(5/2)x-3/2}}} Reduce.



So the equation {{{y=(5/2)x-3/2}}} is now in slope intercept form {{{y=mx+b}}} where the slope is {{{m=5/2}}} and the y-intercept is {{{b=-3/2}}} note: the y-intercept is the point *[Tex \LARGE \left(0,-\frac{3}{2}\right)]