Question 152986
Formula to use:
{{{tan (A+B) = (tan A + tan B)/(1-tan Atan B)}}}
Also note that
{{{tan(pi/3)=sqrt(3)}}}
{{{tan(pi/4)=1}}}

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{{{tan (pi/3+pi/4)}}}
= {{{(tan (pi/3) + tan (pi/4))/(1-tan (pi/3)tan (pi/4))}}}
= {{{(sqrt(3)+1)/(1-sqrt(3)*1)}}}
= {{{(sqrt(3)+1)/(1-sqrt(3))}}}
= {{{((sqrt(3)+1)(1+sqrt(3)))/((1-sqrt(3))(1+sqrt(3)))}}}
= {{{((sqrt(3)+1)(sqrt(3)+1))/((1-sqrt(3))(1+sqrt(3)))}}}
= {{{(sqrt(3)+1)^2/((1-sqrt(3))(1+sqrt(3)))}}}
= {{{(3+2sqrt(3)+1)/(1-3)}}}
= {{{(4+2sqrt(3))/(-2)}}}
= {{{-2-sqrt(3)}}}