Question 152951


{{{(3/4)x+2y=3}}} Start with the given equation.



{{{4((3/cross(4))x+2y)=4(3)}}} Multiply both sides by 4 to clear the fractions.



{{{3x+8y=12}}} Distribute and multiply.



{{{8y=12-3x}}} Subtract {{{3x}}} from both sides.



{{{8y=-3x+12}}} Rearrange the terms.



{{{y=(-3x+12)/(8)}}} Divide both sides by {{{8}}} to isolate y.



{{{y=((-3)/(8))x+(12)/(8)}}} Break up the fraction.



{{{y=-(3/8)x+3/2}}} Reduce.



So the equation {{{y=-(3/8)x+3/2}}} is now in slope intercept form {{{y=mx+b}}} where the slope is {{{m=-3/8}}} and the y-intercept is {{{b=3/2}}} note: the y-intercept is the point *[Tex \LARGE \left(0,\frac{3}{2}\right)]