Question 152942
Given:
{{{f(x) = (2x^2-6x)^(1/3)}}} This is just another way of expressing the cube root of an expression.
Find:
{{{f(3)}}} So you simply substitute 3 for every x in the given expression:
{{{f(3) = (2(3)^2-6(3))^(1/3)}}}
{{{f(3) = (18-18)^(1/3)}}}
{{{f(3) = 0}}}
The domain is all the possible values of the independent variable (x), and this was given as x = 3, so it's just 3.