Question 152918
Here's one
{{{1/(x-1)=0}}}
There is no x you can choose that solves that equation.
I can get close by choosing really large x but it will never equal zero.
.
.
.
{{{x^2+1=0}}}
Again no solution because whenever I square a number, it will be greater than or equal to zero and never -1, which would allow you to solve the equation. 
.
.
.
You will see later on that there are solutions to those equations but not in the traditional sense of a solution that you think of right now.