Question 152791
(3+2i)(3-2i)
Solution:
Using the formula (a+b)(a-b)=a^2 - b^2 to expand (3+2i)(3-2i), we have
(3+2i)(3-2i)
=3^2 - (2i)^2
= 9 - 2^2*i^2
= 9 - 4*(-1)
= 9 + 4
= 13
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8/-2i
Solution:
Our goal is to remove i from the denominator. It can be achieved by multiply both the denominator and numerator by i.

8/(-2i)
= 8*i/(-2i*i)
= 8i/(-2*i^2)
= 8i/[-2*(-1)]
= 8i/2
= 4i