Question 22841
Get the y terms on one side (the left side) and all the other terms to the right side, but adding -2x to each side:
2x + 3y = 6
2x - 2x + 3y = -2x + 6
3y = -2x + 6

Next, divide both sides by 3 to undo the 3.  It can be done in two ways.  Here is the first way:
{{{(3y)/3 = (-2x+6)/3}}}
{{{y= (-2x+6)/3}}}


OR the second way:
{{{(3y)/3 = (-2x)/3 + 6/3}}}

{{{ y = (-2/3)x + 2}}}


R^2 at SCC