Question 152617

{{{(3x - 4)(3x^2 - 2x + 3) }}} Start with the given expression.



{{{3x (3x^2 - 2x + 3)- 4(3x^2 - 2x + 3)}}} Expand. Remember, {{{(A+B)(C+D+E)=A(C+D+E)+B(C+D+E)}}}



{{{(3x )*(3x^2 )+(3x )*(- 2x )+(3x )*( 3)+(- 4)*(3x^2 )+(- 4)*(- 2x )+(- 4)*( 3)}}} Distribute.



{{{9*x^3-6*x^2+9*x-12*x^2+8*x-12}}} Multiply.



{{{9*x^3-18*x^2+17*x-12}}} Now combine like terms.



 So {{{(3x - 4)(3x^2 - 2x + 3) }}} expands to {{{9*x^3-18*x^2+17*x-12}}}.



In other words, {{{(3x - 4)(3x^2 - 2x + 3) =9*x^3-18*x^2+17*x-12}}}.