Question 152558
You're eqn will come up:
$Rental charge + ($Rate)(No. of miles driven) = $ Cost
Showing this in figures: {{{x=dollar/mile}}}, {{{C=cost}}}in dollars
$25+ ($x/mile)(no. of miles driven) = $Cost
$25 +($x/mile)(320 miles)= $89 ------------------> eqn 1
{{{(x/cross(mile))(320cross(miles))=89-25}}}
{{{x=64/320}}}
x=$0.20
There you go the rental car charge $0.20/mile  driven plus $25 flat rate
In doubt? go back eqn 1:
{{{25+(0.20/cross(mile))(320cross(miles))=89}}}
{{{25+64=89}}}
{{{89=89}}}
</pre><font size=4><b>Thank you,
Jojo</pre>