Question 152604

<pre><font size = 4 color = "indigo"><b>
{{{1/u + 5/(u-2) = 4/(u-2)}}}

Put parentheses around all the terms:

{{{(1/u) + (5/(u-2)) = (4/(u-2))}}}

The LCD is {{{u*(u-2)}}}.  Put that over 1
like this {{{u*(u-2)/1}}}. Put parentheses
around it like this {{{(u*(u-2)/1)}}}.

Multiply every term by it:

{{{(1/u)(u*(u-2)/1) + (5/(u-2))(u*(u-2)/1) = (4/(u-2))(u*(u-2)/1))}}}

Cancel whatever will cancel:

{{{(1/cross(u))(cross(u)*(u-2)/1) + (5/(cross(u-2)))(u*(cross(u-2))/1) = (4/(cross(u-2)))(u*(cross(u-2))/1))}}}

All that's left is

{{{(u-2)+5u=4u}}}

{{{u-2+5u=4u}}}

{{{6u-2=4u}}}

{{{6u=4u+2}}}

{{{2u=2}}}

{{{u=1}}}

This does not cause any denominators
to become 0 in the original, so it
is the solution.

Edwin</pre>