Question 152547
I'm not sure if you mean
1.{{{(4/5)/(n+13)}}}
or if you mean
2.{{{(4/5)/(n)+13}}}
Either way, here goes.
Substitute for n=1/5,
1.{{{(4/5)/(n+13)=(4/5)/((1/5)+13)}}}
You need a common denominator to add fractions.
1.{{{(4/5)/(n+13)=(4/5)/((1/5)+(65/5))}}}
1.{{{(4/5)/(n+13)=(4/5)/(66/5)}}}
Dividing by a fraction is equivalent to multiplying by the reciprocal.
1.{{{(4/5)/(n+13)=(4/5)/(66/5)=(4/5)(5/66)}}}
1.{{{(4/5)/(n+13)=(4/5)/(66/5)=2/33}}}
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And now for 2.
2.{{{(4/5)/(n)+13=(4/5)/(n)+13}}}
2.{{{(4/5)/(n)+13=(4/5)/(1/5)+13}}}
2.{{{(4/5)/(n)+13=(4/5)*(5/1)+13}}}
2.{{{(4/5)/(n)+13=4+13}}}
2.{{{(4/5)/(n)+13=17}}}