Question 152449
{{{HCl+H2O=210ml}}} ---------> working eqn
but {{{H2O}}} is 120ml more than {{{HCl}}} ---> {{{H2O=HCl+120ml}}}
Substituting,
{{{HCl+HCl+120=210}}}
{{{2HCl=210-120=90ml}}}
{{{cross(2)HCl/cross(2)=cross(90)45ml/cross(2)}}}
{{{HCl=45ml}}}
For {{{H20=45+120=165ml}}}
Simply add to check via working eqn:
{{{45+165=210}}}
{{{210ml=210ml}}}
Thank you,
Jojo