Question 152498
consecutive odd integers= x, x+2, x+4
(x+4)^2=(x+2)^2+264


Simplify
x^2+8x+16=x^2+4x+4+264


Combine like terms on each side
x^2+8x+16=x^2+4x+268


Subtract 4x from both sides
x^2+4x+16=x^2+268


Subtract 268 from both sides
x^2+4x-252=x^2


Subtract x^2 from both sides
4x-252=0


Add 252 to both sides
4x=252


Divide both sides by 4
x=63


consecutive odd integers= x, x+2, x+4
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Answer: 63, 65, and 67