Question 152467
Absolute value problems are really two problems in one. 
The positive solution:
{{{2<abs(x)-8}}}
{{{2<x-8}}}
{{{10<x}}}
{{{x>10}}}
The negative solution:
{{{2<abs(x)-8}}}
{{{2<-x-8}}}
{{{10<-x}}}
{{{x<-10}}}
In interval notation that would be,
({{{-infinity}}},{{{-10}}})U({{{10}}},{{{infinity}}})