Question 152389
{{{((27*a^3*b^2*c^5)/(45a^4c^2))^3=((3^3*a^3*b^2*c^5)/(5*3^2*a^4c^2))^3
=((3^(3-2)*b^2*c^(5-2))/(5*a^(4-3)))^3=((3^1*b^2*c^3)/(5*a^1))^3
=(3^(1*3)*b^(2*3)*c^(3*3))/(5^3*a^(1*3))
=(3^3*b^6*c^9)/(5^3*a^3)
=(27*b^6*c^9)/(125*a^3)}}}