Question 152335
An equation for the line that is parallel to the line: y = -3x and which passes through the point (3, 0).
First, you should recall that parallel lines have the same slope.
The given line has  a slope: m = -3, so the new line will have a slope of: m = -3.
So you can start by writing:
y = -3x+b Now you need to find the value of b, the y-intercept.  This can be done by substituting the x- and y-coordinate values of the given point (3, 0) into the equation y = -3x+b and solving for b.
0 = -3(3) + b
0 = -9 + b
b = 9
Now you can write the final equation of the line that is parallel to the line whose equation is y = -3x and which passes through the point (3, 0)
{{{highlight(y = -3x+9)}}}